find two consecutive even integers such that twice the smaller is 16 more than the larger

Define x:
Let one of the numbers be x.
The other number is x + 2

Construct equation:
twice the smaller is 16 more than the larger
⇒2x = x + 2 - 16

Solve x:
2x = x + 2 - 16
x = -14

Find the two numbers:
Smaller number = x = -14
Larger number = x + 2 = -12

Answer: The two numbers are -14 and -12