Let ​ f(x)=x^2−13x+30 . What are the zeros of the function? Enter your answers in the boxes.

The values of x for which the function is equal to zero are;x = 10x= 3Zero of a FunctionThis is determined by by finding the x-values that's make the polynomial equal zero.To determine this, we have to solve for the quadratic equation.[tex]y=x^2-13x+30[/tex]Quadratic formulaUsing quadratic formula[tex]x = \frac{-b+- \sqrt{b^2 - 4ac} }{2a} \\[/tex]Let's get the variable in the equation.[tex]a = 1, b = -13, c = 30[/tex]substituting the values into the equation;[tex]x = \frac{-b+-\sqrt{b^2 - 4ac} }{2a} \\x = \frac{-(-13)+-\sqrt{(-13)^2-4*1*30} }{2(1)}\\x = \frac{13+7}{2}\\ x = 10 \\or\\x = \frac{6}{2}\\ x = 3[/tex]The values of x that will make the function equal zero are 10 and 3Let's plug this into the equation and solvefor x = 10[tex]y = x^2-13x+30\\y = (10)^2-13(10)+30\\y = 100-130+30\\y = 0[/tex]For x = 3[tex]y = x^2 - 13x + 30\\y = (3)^2-13(3) + 30\\y = 0[/tex]From the calculations above, the values of x for which the function is equal to zero are;x = 10x= 3Learn more on functions of polynomials here;