When fritz drives to work his trip takes 48 ​minutes, but when he takes the train it takes 40 minutes. find the distance fritz travels to work if the train travels an average of 6 miles per hour faster than his driving. assume that the train travels the same distance as the car?

Let x be the speed when Fritz is driving
x + 6 will be the train speed
Converting minutes to hrs
48 mins = 48/60 = 4/5 hrs
40 mins = 40/60 = 2/3 hrs

Remember formula distance = rate * time
distance driving = (4/5)x
distance train traveling = (2/3)(x+6)

The train travels the same distance as the car
4/5x = 2/3(x+6)
4/5x = 2/3x + 4
4/5x - 2/3x = 4
basic elementary school math
2/15x = 4
2x = 40
x = 30 miles/hrs is the speed he driving.
distance train traveling = 2/3(30 + 6) = 24 miles 
check with the distance he driving
4/5(30) = 24 miles