What is the sector with a central angle of 185 degrees and a diameter of 6.4 m? Round to the nearest tenth. 66.1m^2 5.3m^2 16.5m^2 21.0m^2

The area of a sector is 
     [tex]A=\frac{1}{2}r^2\theta =\frac{1}{2}\left(3.2\:m\right)^2\left(185\cdot \frac{\pi }{180}\right)=16.5\:m^2[/tex]

The answer is 16.5 square meters.