Recall the equation for a circle with center ( h , k ) and radius r . At what point in the first quadrant does the line with equation y = 2.5 x + 5 intersect the circle with radius 5 and center (0, 5)?

Answer:(2.23, 7,57)Step-by-step explanation:equation of this circle isx^2 + (y - 2)^2 = 36y = 2.5x + 2Substitute for y in the equation of the circle:-x^2 + (2.5x + 2 - 2)^2 = 36x^2 + 6.25x^2 = 36x^2 = 36 / 7.25  x = +/-   6  /  2.693  =  +/- 2.228when x = 2.228 y = 2.5(2.228) + 2 =  7.57    to nearest hundredthwhen x = -2.228 y = 2.5(-2.228) + 2 =   -3.57So they intersect at 2 points but the intersect in the first quadrant is at (2.23, 7,57)        to nearest hundredth.