Simplify quantity 18 x minus 6 over 9 x to the fifth power all over quantity 15 x plus 5 over 21 x squared

Going off of your description, I got and solved this equation:

[tex] \frac{ \frac{18x-6}{9x^{5} }}{ \frac{15x+5}{21x^{2} } } [/tex]

I simplified it to:

[tex] \frac{ \frac{6(3x-1)}{9x^{5}} }{ \frac{5(3x+1)}{21 x^{2} } } [/tex]

I then simplified again and flipped the second fraction to get a multiplication problem:

[tex] \frac{2(3x-1)}{3 x^{5} }( \frac{21 x^{2} }{5(3x+1)} [/tex]

Which then simplifies to your answer:

[tex] \frac{14(3x-1)}{5 x^{3}(3x+1)} [/tex]