The average adult men The average weight of adult men is 183 pounds with a standard deviation of 41 pounds. thirty men were asked their weight and the mean was calculated to be 180, test the hypothesis that the mean is not 183 pounds using a=.05

[tex]Conditions: \\ *Sample \ of \ thirty \ random \ adult \ men \\ *Thirty \ adult \ men\ are \ independent \\ *Thirty \ men \ are \ less \ than \ 10 \% \ of \ all \ adult \ men \\ *Thirty \ is \ large \ enough \ by \ CLT \ to \ use \ t-dist \\ \mu = True \ mean\ weight \ of \ adult \ men \\ \\ t-dist \ curve \ must \ be \ drawn \ with \ center \ at \ 183 \ and \ the \ test \\ statistic \ at \ 180, \ and \ 186 \ shade \ to \ the \ left \ and \ right \\ H_0: \mu=183, H_a: \mu \neq 183 [/tex] [tex]t = \frac{180-183}{41/ \sqrt{30}} = -.401 \\ p = .692 \\ With \ a \ p-value \ of \ .692 \ \textgreater \ \alpha \ at \ .05, \ we \ fail \ to \ reject \ the \\ null \ and \ cannot \ support \ that \ the \ true \ mean \ of \ adult \ men \\ is \ not \ 183 \ lbs[/tex]