The second side of a triangular deck is 4 feet longer than the shortest​ side, and the third side is 4 feet shorter than twice the length of the shortest side. if the perimeter of the deck is 56 ​feet, what are the lengths of the three​ sides?

Let's assume first side as shortest sideand shortest side =xwe are given the second side of a triangular deck is 4 feet longer than the shortest​ sideso, second side is [tex] =x+4 [/tex]the third side is 4 feet shorter than twice the length of the shortest sideso, third side is [tex] =2x-4 [/tex]now, we are given perimeter =56so, first side + second side + third side =56we get [tex] x+x+4+2x-4=56 [/tex][tex] x+x+2x=56 [/tex]now, we can solve for x[tex] 4x=56 [/tex][tex] x=14 [/tex]so, first side is 14 feetSecond side is:[tex] =14+4 [/tex][tex] =18 feet [/tex]Third side is:[tex] =2*14-4 [/tex][tex] =24feet [/tex]