The sum of the first 30 terms of the sequence an=6n+5 is

Question

Answer:

First term a1 = 6+5 = 11
second term = 12+5 = 17

common difference = 6

Sum of n terms:-
Sn = (n/2) [ 2a1 + d(n - 1)]
Sum of 30 terms:-
S30 = (30/2)[ 2*11 + 6(30-1)]
= 15 * ( 22 + 174)
= 15 * 196
= 2940 Answer