The sum of three consecutive odd integers is 41 less than four times the largest. Find the numbers.

Let n = 1st odd integer
   n + 2 = 2nd odd integer
   n + 4 = 3rd odd integer
SUM:
n + n + 2 + n + 4 = 4(n + 4) - 41
3n + 6 = 4n + 16 - 41
3n + 6 = 4n - 25
31 = n
ANSWER: 31, 33, 35