Triangle ABC has vertices A(–2, –3), B(–5, –3), and C(–4, –2). The triangle is rotated 90° counterclockwise around the origin.What is the correct set of image points for triangle A’B’C’?A’(3, 2), B’(3, 5), C’(2, 4)→→A’(3, –2), B’(3, –5), C’(2, –4)←←A’(–3, –2), B’(–3, –5), C’(–2, –4)A’(–3, 2), B’(–3, 5), C’(–2, 4)Answer is B :)

The answer is the option B: A'(3, -2), B'(3, -5), C'(2, -4). The explanation is shown below: 1. You must apply  the following rule of rotation when the figure is rotated 90° counterclockwise around the origin: [tex](x,y)[/tex]→[tex](-y,x)[/tex] 2. Then, as you can see, you must switch [tex]x[/tex] and [tex]y[/tex] and multiply [tex]y[/tex] by -1. 3. Keeping this on mind, you have that the vertices of the triangle A'B'C' are the following: A(-2,-3)→A'(3,-2) B(-5,-3)→B'(3,-5) C(-4,-2)→C(2,-4) 4. Therefore, you can conclude that the answer is the option B.