Two old rsm students were standing twenty feet apart when they spotted mrs. rifkin. if they immediately run in opposite directions with speeds of 180 feet per minute and 120 feet per minute respectively, how many minutes will pass before they are 2,420 feet apart?
Question
Answer:
Speed of student A is 180 ft/minSpeed of student B is 120 ft/min
Relative speed=(120+180)=300 ft/min
Distance between them is 2420 ft
Time taken for them to meet will be:
time=distance/speed
=(2420-20)/300
=8 min
solved
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10 months ago
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