What is an equation of the line that passes through the point (8,5) and (-6,5)

For this case we have that by definition, the equation of the line in the slope-intersection form is given by:[tex]y = mx + b[/tex]Where:m: It is the slope of the lineb: It is the cut-off point with the y axisWe have two points through which the line passes:[tex](x_ {1}, y_ {1}) :( 8,5)\\(x_ {2}, y_ {2}): (- 6,5)[/tex]We found the slope:[tex]m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {5-5} {- 6-8} = \frac {0} {- 14} = 0[/tex]The slope is zero.Thus, the equation is of the form:[tex]y = b[/tex]We substitute one of the points and find b:[tex](x, y) :( 8,5)\\5 = b\\b = 5[/tex]Finally, the equation is:[tex]y = 5[/tex]Answer:[tex]y = 5[/tex]