What is the area of this figure? Enter your answer in the box. units² An irregular heptagon is graphed on a coordinate plane. The horizontal x-axis ranges from negative 6 to 6 in increments of 1. The vertical y-axis ranges from negative 6 to 6 in increments of 1. The vertices of the heptagon are located at begin ordered pair negative 5 comma 3 end ordered pair, begin ordered pair negative 4 comma 5 end ordered pair, begin ordered pair negative 2 comma 3 end ordered pair, begin ordered pair 3 comma 4 end ordered pair, begin ordered pair 4 comma 3 end ordered pair, begin ordered pair 4 comma negative 3 end ordered pair, and begin ordered pair negative 3 comma negative 3 end ordered pair.

Question
Answer:
We divide the figure in the following areas:
 Area of the two upper triangles:
 Area of triangle 1:
 At1 = (1/2) * (3) * (2) = 3
 Area of triangle 2:
 At2 = (1/2) * (6) * (1) = 3
 Area of the complete lower rectangle
 Ar = (9) * (6) = 54
 Area of the lower triangle:
 At3 = (1/2) * (2) * (6) = 6
 The total area of the figure is:
 At1 + At2 + Ar-At3 = (3) + (3) + (54) - (6) = 54
 answer:
 the area of this figure is 54 units^2
solved
general 10 months ago 4720