find 2 numbers, if their sum is -11 and their difference is 41

Answer:   15, -26Step-by-step explanation:The generic solution to a "sum and difference" problem can be found easily. Let "a" and "b" represent the numbers you seek, and let "s" and "d" represent their sum and difference:   a + b = s   a - b = dAdding these two equations tells you ...   2a = s + d   a = (s + d)/2 . . . . . . divide by the coefficient of aYou can find "b" several different ways. One way is to subtract the second equation from the first:   2b = s - d   b = (s - d)/2 . . . . . . divide by the coefficient of bSo, the second number can be found from any of ...b = s - ab = a - db = (s - d)/2____For the numbers given here, s=-11, d=41, the two numbers are ...   a = (-11 +41)/2 = 15   b = -11 -15 = -26The two numbers are 15 and -26.