What is true about this relationship?y= /4+ xO A.It is an odd function.OB.It is not a function.OC.It is an even function.OD.It is neither an odd nor an even function
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It is neither an odd nor an even functionExplanation:I'll assume that the relationship is:[tex]y=4+x[/tex]In function notation, we can write this as follows:[tex]f(x)=4+x[/tex]For any even function it is true that:[tex]f(x)=f(-x)[/tex]For any odd function it is true that;[tex]f(-x)=-f(x)[/tex]Applying these rules to our function:RULE FOR EVEN FUNCTION:[tex]f(x)=4+x \\ \\ f(-x)=4+(-x) \therefore f(-x)=4-x \\ \\ f(x)\neq f(-x)[/tex]It is not an even function!RULE FOR ODD FUNCTION:[tex]f(x)=4+x \\ \\ -f(x)=-4-x \\ \\ f(-x)=4+(-x) \therefore f(-x)=4-x \\ \\ f(-x)\neq -f(x)[/tex]It is not an odd function!__________________________________So the conclusion is:It is neither an odd nor an even functionLearn more:Even function:
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