In this triangle, the product of sin B and tan C is _____ , and the product of sin C and tan B is _______.

In this triangle, the product of sin B and tan C is c/a or cos B, and the product of sin C and tan B is b/a cos C. We determine these as follows:
sin B tan C = b/a (c/b) = c/a
sin C tan B = c/a (b/c) = b/a
Hope this answers the question. Have a nice day.
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