if ∆GFE ~ ∆CBE, find the value of x

[tex] \dfrac{4x - 1}{x + 5} = \dfrac{60}{24} [/tex]

[tex] \dfrac{4x - 1}{x + 5} = \dfrac{5}{2} [/tex]

[tex] 5(x + 5) = 2(4x - 1) [/tex]

[tex] 5x + 25 = 8x - 2 [/tex]

[tex] -3x = -27 [/tex]

[tex] x = 9 [/tex]